Question

O valor de y= x4 + x2 sobre x + 1, para x=1/2 ?

Answer 1

y= x^4 + x^2 /x+1
y= 1/2^4 + 1/2^2 /1/2+1
y=1/16 + 1/4 / 1/2 +1
fazendo minimo de 16 e 4, e 2 e 1

y=4+1/4 / 1+2/2
y=5/4 / 3/2
y= 5/4 x 2/3
y= 10/12

y=5/6