Question

aplique o teorema de Newton para desenvolver (2x-1)³

Answer 1

Resposta:

(2x-1)³ =

C3,3 * (2x)³ * (-1)³⁻³ + C3,2 * (2x)² * (-1)³⁻² +C3,1  * (2x)¹ * (-1)³⁻¹

+C3,0 * (2x)⁰ *(-1)³⁻⁰

=(2x)³ +3 * 4x²* (-1) + 3 * (2x)* (1)  + (-1)³

=8x³-12x² +6x-1

Answer 2

Resposta:

(2x-1)³ =

(2x-1)(2x-1)(2x-1)

(4x²-2x-2x+1)(2x-1)

(4x²-4x+1)(2x-1)

8x³-8x²+2x-4x²+4x-1

8x³-8x²-4x²+2x+4x-1

8x³-12x²+6x-1