Question

Determine o valor de "X" usando a fórmula de bhaskara:

a) x^2+x-20=0
b) x^2-3x+2=0
c) 5x^2-20=0
d) x^2-4x-96=0​

Answer 1

A) x² + x -20 = 0

Δ= 1 - 4. 1 . -20

Δ= 81

-1 ± 9

x' = 8/2 = 4

x'' = -10/2 = -5

S {-5,4}

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b) x² -3x + 2 =0

Δ= 9 . -4 . 1 . 2

Δ= 1

3±1/2

x' = 4/2 = 2

x'' = 2/2 = 1

S {1,2}

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c) 5x² - 20 = 0

x² = 20:5

x = ±√4

S{ -2,2 }

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d) x² -4x-96 = 0

Δ= 16 - 4 . -96

Δ= 400

4±√400/2

x' = 4+20/2 = 22

x'' = 4-20/2 = -8

S {-8,22}

Answer 2

Resposta:

A)

fórmula = ∆= b^2 - 4 . a . C

∆= 1^2- 4 . 1 . (-20)

∆= 1 + 80

∆= 81

fórmula = X= -b +- √∆

2.a

x = - (-20) +- √81

2.1

x= 20 +- 9

2

x = 20 + 9 = 29= 14,4

2 2

x= 20 - 9 = 11= 5,5

2 2