Question

1-Calcule
A) P5+A5,2
B) P2+A6,3+C6,2
C)P8-A8,2
D) P9-A6,4+C7,3
E)P6+A4,3+C5,2
Ajuda-me ?​

Answer 1

Resposta:

$A)P_5+A_{5,2}=5!+\frac{5!}{3!}=120+5.4=120+20=140\\\\B) P_2+A_{6,3}+C_{6,2}=2!+\frac{6!}{3!}+\frac{6!}{4!2!}=2+6.5.4+\frac{6.5}{2}=2+120+15=137\\\\C) P_8-A_{8,2}=8!-\frac{8!}{6!}= 40320-56=40264\\\\D) P_9-A_{6,4}+C_{7,3}=9!-\frac{6!}{2!}+\frac{7!}{4!.3!}=362880-360+35=362555\\\\E) P_6+A_{4,3}+C_{5,2}=6!+\frac{4!}{1!}+\frac{5!}{3!.2!}=720+24+10=754$

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