Question

determine as coordenadas do vértice da função f(x)=x²-3x+2

Answer 1

f(x)= x²-3x+2

xv=-b /2a

xv=-(-3) /2.1

xv=3/2

Δ=b² -4.a.c

∆=9 -4.1.2

∆=9 -8

∆=1

yv= -Δ /4a

yv= -1/ 4.1 = -1/4

V {3/2, -1/4}