Question

Determine as medidas dos angulos internos destes trapezios,sendo DC//AB

Answer 1

Resposta:

Explicação passo-a-passo:

a)

118+x=180

x=180-118=62°

y+48°32'=180

y=180-48°32'

y=131°28'

b)

x+90=180

x=180-90=90

y+z=180 onde y=180-74=106

106+z=180

z=180-106

x=74°

c)

132+x=180

x=180-132=48°

x+y=180  

48+y=180

y=180-48=132°

d)

x+12+x=180

2x+12=180

2x=180-12

2x=168

x=168/2

x=84°

2y+y=180

3y=180

y=180/3

y=60°