Question

Resolva as equação
A) (n-1)! =10
(n-2)!


B) 8 (x+3)!
(x+4)!

Answer 1

(n-1)! / (n-2)! = 10

(n-1)(n-2)! / (n-2)! = 10

(n-1) = 10

n = 11 ✓

8(x+3)! = (x+4)!

8(x+3)! = (x+4)(x+3)!

8 = (x+4)

x = 8 -4

x = 4 ✓

Answer 2

a) (n-1)! =10(n-2)!

(n-1)(n-2)! =10(n-2)!

n-1=10

n=10+1=11

b)

8(x+3)! =(x+4)!

8(x+3)! =(x+4)(x+3)!

8=x+4

x+4=8

x=8-4

x=4