Question

Números complexos
a+bi+i^2=5+6i
a-b=?

Answer 1

$a+bi+i^2~=~5+6i\\\\\\a+bi+(-1)~=~5+6i\\\\\\a+bi~=~5+6i+1\\\\\\a+bi~=~6+6i\\\\\\Igualando~as~Partes~Reais~e~igualando~as~Partes~Imaginarias:\\\\\\\left\{\begin{array}{ccc}a&=&6\\b&=&6\end{array}\right\\\\\\Efetuando~a~subtracao~pedida~no~enunciado:\\\\\\a-b~=~6-6~=~\boxed{0}~~\checkmark$