Question

questão 66
${2x}^{2} - {20x}^{2} - 12 = 0$
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Answer 1

2x² -20x -12 = 0 ==> : (2)

x² -10x -6 = 0

∆= 100+24=124 => √∆= √4.31 = 2√31

x = 10±2√31/2

x' = 10+2√31/2 = 5 +√31 ✓

x"= 10-2√31/2 = 5 -√31 ✓