Question

Preciso da resposta urgente

Answer 1

$x = \sqrt{12} = \sqrt{2 \times 2 \times 3} = 2 \sqrt{3}$

$(y - 1 )^{2} = 3 \\ y^{2} - 2y + 1 = 3 \\ y^{2} - 2y - 2 = 0 \\ y = \frac{ - ( - 2) + - \sqrt{( - 2)^{2} - 4 \times 1 \times ( - 2)}}{2 \times 1} \\ y = \frac{2 + - \sqrt{4 + 8} }{2} \\ y = \frac{2 + \sqrt{12} }{2} \\ y = \frac{2 + 2 \sqrt{3} }{2} \\ y = 1 + \sqrt{3}$

$p = 2 \sqrt{3} + 2 \sqrt{3} + 1 + \sqrt{3} + 1 + \sqrt{3} \\ p = 6 \sqrt{3} + 2$

$a = (2 \sqrt{3} )(1 + \sqrt{3} ) \\ a = 2 \sqrt{3} + 2 \times 3 \\ a = 6 + 2 \sqrt{3}$

Opção E)