Question

qual a area do triangulo cujo entre verticies sao (0,1) (2,9) (6,-1)​

Answer 1

Resposta:

Distancias;

$dP_{1}P_{2}=2\sqrt{17}\\dP_{2}P_{3}=2\sqrt{29}\\dP_{1}P_{3}=2\sqrt{10}\\\\hipotenusa=P_{2}P_{3}\\altura=P_{1}P_{2}\\base=P_{1}P_{3}\\\\A_{t}=\frac{(2\sqrt{10})*(2\sqrt{17})}{2}\\A_{t}=\sqrt{10}*\sqrt{17}\\A_{t}=13,04\boxed {u.m.}^{2}$

Explicação passo-a-passo: