Question

qual o termo medio no desenvolvimento de (x+4)^6​

Answer 1

$tp + 1 = ( - 1)^{p} \times \binom{n}{p} \times x ^{p - 1} \times {a}^{p}$

p+1=4

p=4-1=3

$t3 + 1 = ( - 1)^{3} \times \binom{6}{3} \times x^{6 - 3} \times {4}^{3}$

$t3 + 1 = - 1 \times \frac{6!}{3!3!} \times {x}^{3} \times 64$

$t4 = - 1 \times 20 \times {x}^{3} \times 64$

$t4 = - 1280 {x}^{3}$