Question

alguém ajuda trigonometria??? por favor???

Answer 1

Lei dos senos:

$\frac{\sqrt6}{sen60}=\frac{x}{sen45} \\ \\ \frac{\sqrt6}{\frac{\sqrt3}{2}}=\frac{x}{\frac{\sqrt2}{2}} \\ \\ x=\frac{\frac{\sqrt{12}}{2}}{\frac{\sqrt3}{2}} \\ \\ \boxed{x=\frac{\sqrt{12}}{\sqrt3}=\sqrt4=2}$

Answer 2

√6 / sen60° = x/sen45°

√6 / √3/2 = x/ √2/2

√12/2 = √3x/2

√12 = √6x/2

√24  = √6x

x = √24/√6

x= √4

x = 2