Question

x2+16x-36=0 Com calculo na fórmula de Baskara​

Answer 1

Resposta:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}+16x-36=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=16~e~c=-36\\\\\Delta=(b)^{2}-4(a)(c)=(16)^{2}-4(1)(-36)=256-(-144)=400\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(16)-\sqrt{400}}{2(1)}=\frac{-16-20}{2}=\frac{-36}{2}=-18\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(16)+\sqrt{400}}{2(1)}=\frac{-16+20}{2}=\frac{4}{2}=2\\\\S=\{-18,~2\}$