Question

m) log; x – 6 log x +9=0

Answer 1

Resposta:

Explicação passo-a-passo:

log²x - 6 logx + 9 = 0

Δ = b² - 4ac

Δ = (-6)² - 4.1.9

Δ = 36 - 36

Δ = 0

logx = (-b ±√(b² - 4ac) : 2a

logx = [-(-6) ±0]/2.1

logx = 6/2

logx = 3

x = 10³

x = 1000