Question

oi alguém sabe resolver essa conta?​

Answer 1

$b) \: \frac{x - 1}{3} + \frac{x + 2}{x -1 } = x + 1$

$\frac{x - 1}{3} + \frac{x + 2}{x - 1} - x - 1 = 0$

$\frac{( {x - 1)}^{2} + 3(x + 2) - 3x \times (x - 1) - 3(x - 1) }{3(x - 1)} = 0$

$\frac{ {(x - 1)}^{2} + 3x + 6 - {3x}^{2} + 3x - 3x + 3 }{3(x - 1)} = 0$

$\frac{ {x}^{2} - 2x + 1 + 9 - {3x}^{2} + 3x }{3( x - 1)} = 0$

$\frac{ - {2x}^{2} + x + 10 }{3(x - 1)} = 0$

$- {2x}^{2} + x + 10 = 0 \\ {2x}^{2} - x - 10 = 0$

$x = \frac{ - ( - 1) + - \sqrt{( - 1) ^{2} - 4 \times 2 \times ( - 10) } }{2 \times 2}$

$x = \frac{1 + - \sqrt{1 + 80} }{4}$

$x = \frac{1 + - \sqrt{81} }{4}$

$x = \frac{1 + - 9}{4}$

$x = \frac{1 + 9}{4} = \frac{5}{2} \\ x = \frac{1 - 9}{4} = - 2$