Question

se log2a=3, então o logaritmo de 10 na base a é

Answer 1

log2a=3, isto é, a³ = 2

log10a=?

$\frac{1/3}{1/3} log_{a}10\\\\frac{log_{a^3}10}{1/3} \\\\frac{log_{2}10}{1/3} \\\log_{2}\sqrt[3]{10} \\\\frac{log 10^{1/3}}{log 2} \\\frac{1/3}{0.301} = 1,107$