Question

5) Calcule:
a) (2x2-9x+2)+(3x2+7x-1)=
b) (5x2+5x-8)+(-2x2+3x-2)=
c) (4x-y-1)-(9x+y+3) =
d) (-2a2-32+6)-(-4a2-52+5)=
e) (x+5)-(x+2) =
f) (3x+2).(2x+1)=
g) (x+7).(x-4)=
h) ( 12x2 - 8x) : (+2x) =
i) (3y3 + 6y2) : (3y) =
j) ( 10x2 + 6x) : (-2x) = k) (4x³-9x): (+3x)​

Answer 1

Resposta:

a) 2x2-9x+2 +3x2+7x-1=

2x2+3x2-9x+7x+2-1=

5x2-2x+1

b)(5x2+5x-8)+(-2x2+3x-2)=

5x2-2x2+5x+3x-8-2=

3x2+8x-10

c)4x+9x-y-y-1-3=

13x-2y-4

d)-2a2+4a2-3^2+5^2+6-5=

2a2+16+1=

2a2+17=

a2=-17/2

a= +-√-17/2 (não pertence a R)

e)(x+5)-(x+2)=

x+5-x-2=

5-2=3

f)(3x+2)(2x+1)=

6x2+3x+4x+2=

6x2+ 7x+2

g) (x+7)(x-4)=

x2-4x+7x-28=

X2+3x-28

h)(12x2-8x)÷(2x)=

6x-4

i). (3y3+6y2)÷(3y)=

y2+2y

j) (10x2+6x)÷(-2x)=

-5x-3

k)(4x3-9x)÷(3x)=

4/3x2-3