Question

a) 4 elevado a 5. 4³ b) 2 elevado a 7 . 2 elevado a 8 c) (2 elevado a 9)³​

Answer 1

a)

${4}^{5} \times {4}^{3} = {4}^{5 + 3} = {4}^{7}$

b)

${2}^{7} \times {2}^{8} = {2}^{7 + 8} = {2}^{15}$

c)

$( {2}^{ {9})^{3} } = {2}^{9 \times 3} = {2}^{27}$