Question

f(y)=×^2+1÷√×
resolve essa derivada aí ​

Answer 1

$y=\frac{x^{2} +1}{\sqrt{x}}$

Aplica a regra do quociente:

$=\frac{(x^{2} +1)'*\sqrt{x} - (x^{2} +1)*(\sqrt{x})'}{(\sqrt{x})^{2} }\\\\=\frac{2x*\sqrt{x} - (x^{2} +1)*(\frac{1}{2\sqrt{x}})}{x}\\\\=\frac{2x*\sqrt{x} -(\frac{x^{2} +1}{2\sqrt{x}})}{x}$