Question

Resolva a equação de 2° grau usando a formula de bhaskara e dê o conjunto solução.

X² + 3X - 6= -8

Answer 1

Resposta:

Explicação passo-a-passo:

x²+3x-6= -8

x²+3x-6+8=0

x²+3x+2=0

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}+3x+2=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=3~e~c=2\\\\\Delta=(b)^{2}-4(a)(c)=(3)^{2}-4(1)(2)=9-(8)=1\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(3)-\sqrt{1}}{2(1)}=\frac{-3-1}{2}=\frac{-4}{2}=-2\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(3)+\sqrt{1}}{2(1)}=\frac{-3+1}{2}=\frac{-2}{2}=-1\\\\S=\{-2,~-1\}$

Answer 2

${3}^{2} - 4(1)(2) \\ 9 - 8 \\ y = 1 \\ - (3) + - \sqrt{1} \div 2 \\ x1 = - 1 \\ x2 = - 2$