Question

5x ao quadrado - 3x - 2=0​

Answer 1

Resposta:

Explicação passo-a-passo:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~5x^{2}-3x-2=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=5{;}~b=-3~e~c=-2\\\\\Delta=(b)^{2}-4(a)(c)=(-3)^{2}-4(5)(-2)=9-(-40)=49\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-3)-\sqrt{49}}{2(5)}=\frac{3-7}{10}=\frac{-4\div2}{10\div2}=-\frac{2}{5}\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-3)+\sqrt{49}}{2(5)}=\frac{3+7}{10}=\frac{10}{10}=1\\\\S=\{-\frac{2}{5},~1\}$