Question

dado log 2 = 0, 301, log 3 = 0, 477 e log 5 = 0, 699, resolva as expressões:

a) log 2 + log 3 - log 10

b) log 5 . log 2 + log 2

c) log 27 + log 25

d) log 45 - log 18 ÷ log 30

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Answer 1

(a) log2 + log3 - (log2 + log5) =

0,301 + 0,477 - (0,301 + 0,699) =

0,778 - 1 =

-0,222

(b) log5 • log2 + log2 =

0,699 • 0,301 + 0,301 =

0,210399 + 0,301 =

0,511399

(c) log3³ + log5² =

3 • log3 + 2 • log5 =

3 • 0,477 + 2 • 0,699 =

1,431 + 1,398 =

2,829

(d) log(3² • 5) - log(2 • 3²) ÷ log(2 • 3 • 5) =

2 • log3 + log5 - (log2 + 2 • log3) ÷ (log2 + log3 + log5) =

2 • 0,477 + 0,699 - (0,301 + 2 • 0,477) ÷ (0,301 + 0,477 + 0,699) =

0,954 + 0,699 - (0,301 + 0,954) ÷ 1,477 =

1,653 - 1,255 ÷ 1,477 =

1,653 - 0,8496953283 =

0,8033046716