Question

(x³ y³)² + (2x²2y²)²

Answer 1

(x³y³)² + (2x²2y²)²

${x}^{6} {y}^{6} + ( {4x}^{2} {y}^{2} )^{2}$

${x}^{6} {y}^{6} + 16 {x}^{4} {y}^{4}$

Answer 2

Resposta:

Explicação passo-a-passo:

= (x³ y³)² + (2x²2y²)²

= x^6.y^6 + (4x^2.y^2)^2

= x^6.y^6 + 16x^4.y^4