Question

Responda as seguintes equações exponenciais
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Answer 1

Olá vamos ver!

a) 9×+3=243×

9× .9^3=243×

9× .729=243^×

243×/9×=729

(243/9)× =729

27× =729

(3^3)× =3^6

3^3x = 3^6

Logo:

3x=6

x=6/3

x=2

Sol.:{2}

a) (5/3)^2x =27/125

(5/3)^2x=3^3/5^3

(5/3)^2x=(3/5)^3

(5/3)^2x=(3/5)^-3

Logo:

2x=-3

x=-3/2

Sol.:{-3/2}

c) 32^2x+1 =V32

(32^2x+1)^2 =(V32)^2

32^4x+2 = 32^1

Logo:

4x+2=1

4x=1-2

4x=-1

x=-1/4

Sol.:{-3/2}

d)(1/2)×^2-4 =8×+2

(1/2)×^2-4 = (2^3)×+2

(1/2)×^2-4= 2^3x+6

2^-(x^2-4)=2^3x+6

Logo:

-(x^2-4)=3x+6

-x^2+4=3x+6

-x^2-3x+4-6=0

-x^2-3x-2=0

a=-1, b=-3 , c=-2

Usando Bhaskara :

x=-b+/-Vb^2-4ac

x=-2 v x=-1

• Sol.:{-2 ,-1}

Bons estudos!