Question

Calcule a distância entre os pontos A(3,9,1) e B(-7,0,1).

Answer 1

d=√(3+7)²+(9-0)²+(1-1)²

d=√(100)+(81)+(0)

d=√181

Answer 2

Resposta:

$(x,y,z)\\A(3,9,1)\\B(-7,0,1)\\dAB=\sqrt{(x_{a}-x_{b})^{2}+(y_{a}-y_{b})^{2}+(z_{a}-z_{b})^{2}}\\dAB=\sqrt{(3-(-7))^{2}+(9-0)^{2}+(1-1)^{2}}\\dAB=\sqrt{(3+7)^{2}+(9)^{2}+(0)^{2}}\\dAB=\sqrt{(10)^{2}+(9)^{2}}\\dAB=\sqrt{100+81}\\dAB=\sqrt{181}\\\\Distancia.AB=\boxed{\sqrt{181}}$

Explicação passo-a-passo: