Question

3 elevado a x ao quadrado menos 3X = 1 sobre 9​

Answer 1

Olá, tudo bem? Resolvendo essa equação exponencial; assim:

$3^{x^2-3x}=\dfrac{1}{9}\to\\\\\\\not3^{x^2-3x}=\not3^{-2}\to\\\\x^2-3x=-2\to\\\\x^2-3x+2=0\to\\\\\text{F\'ormula Quadr\'atica ou Bhaskara}\to\\\\x=\dfrac{-(-3)\pm\sqrt{(-3)^2-4\times 1\times 2}}{2\times 1}\to\\\\\\x=\dfrac{3\pm\sqrt{9-8}}{2}\to x=\dfrac{3\pm 1}{2}\to\\\\\boxed{x=1}\,\,\text{ou}\,\,\boxed{x=2}$

É isso!!