Question

2+3[x-(3x+1)] = 5[x-(2x-1)]

Answer 1

    2 + 3 × [ x - ( 3x + 1 ) ] = 5 × [ x - ( 2x - 1 ) ] ⇔

⇔ 2 + 3 × ( x - 3x - 1 ) = 5 × ( x - 2x + 1 ) ⇔

⇔ 2 + 3 × ( -2x - 1 ) = 5 × ( -x + 1 ) ⇔

⇔ 2 - 6x - 3 = -5x + 5 ⇔

⇔ -6x + 5x = 5 - 2 + 3 ⇔

⇔ -x = 6 ⇔

⇔ x = -6