Question

Equação do 2 grau x. (x+9)=36​

Answer 1

Resposta:

x(x+9)=36

x²+9x=36

x²+9x-36=0

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}+9x-36=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=9~e~c=-36\\\\\Delta=(b)^{2}-4(a)(c)=(9)^{2}-4(1)(-36)=81-(-144)=225\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(9)-\sqrt{225}}{2(1)}=\frac{-9-15}{2}=\frac{-24}{2}=-12\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(9)+\sqrt{225}}{2(1)}=\frac{-9+15}{2}=\frac{6}{2}=3\\\\S=\{-12,~3\}$

Answer 2

Explicação passo-a-passo:

x ( x+9 ) = 36

x² + 9x = 36

x² + 9x — 36 = 0

• Coeficientes:
• a = 1
• b = 9
• c = -36

• Discriminante:
• ∆ = b² — 4 • a • c
• ∆ = 9² — 4 • 1 • (-36)
• ∆ = 81 + 144
• ∆ = 225

• Bhaskara:
• x¹'² = (-b±√∆)/2•a
• x¹'² = (-9±√225)/2•1
• x¹'² = (-9±√15)/2

• x¹ = (-9+15)/2 = 6/2 = 3

• x² = (-9-15)/2 = -24/2 = -12

Espero ter ajudado bastante!)