Question

(n+3)!/(n-1)!=20 Ajudem se for possível!!!​

Answer 1

(n+3)!/(n-1)!=20

(n+3)(n+2)(n+1)n(n-1)!/(n-1)!=20

(n+3)(n+2)(n+1)n = 20 => ???

ou seria:

(n+3)!/(n+1)!=20

(n+3)(n+2)(n+1)!/(n+1)!=20

(n+3)(n+2) = (5)(4)

n = 2 ✓