Question

reduza o monômio
$3x +4 {x}^{2} - 2 {x}^{2} + 0.6x + 0.7 {x}^{2}$
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Answer 1

Resposta:

$\frac{27x^{2}+36x}{10}$

Explicação passo-a-passo:

$3x+4x^{2}-2x^{2}+0.6x+0.7x^{2} =\\2x^{2}+3x+\frac{6}{10}x+\frac{7}{10}x^{2}=\\2x^{2}+\frac{7}{10}x^{2}+3x+\frac{6}{10}x=\\\frac{20}{10}x^{2}\frac{7}{10}x^{2}+\frac{30}{10}x+\frac{6}{10}x=\\\frac{27}{10}x^{2}  +\frac{36}{10}x=\\\frac{27x^{2}+36x}{10}$