Question

x² + 4x - 12 = 0 delta

Answer 1

x^2+4x-12=0
delta=b^2-4ac
delta=4^2-4.1.(-12)
delta=16+48
delta=64
x=-b-/+ raiz de delta/2a
x=-4-8/2.1
x=-12/2
x=-6
x=-4+8/2.1
x=4/2
x=2

Answer 2

a=1 b=4 c=-12

delta= b²-4ac
delta= (4)² - 4(1)(-12)
delta =16 +48
delta = 64


-b +- raiz de delta /2(a)
-4 +- 8/2
x¹ -4+8/2 = 4/2 = 2
x² -4-8/2 = -12/2 = -6