Question

log x na vase 8 + log 2x na base 8

Answer 1

$\log_{a } b + \log_{a} c = \log_{a} (b.c);,$;, $\log_{8 } x + \log_{8} 2x = \log_{8} (x.2x)= \log_{8} 2 x^{2} = 2\log_{8} 2x$