Question

resolva a equação de 2 grau
-x²+x+12=0​

Answer 1

resolução!

$- {x}^{2} + x + 12 = 0 \times ( - 1) \\ {x}^{2} - x - 12 = 0$

∆ = (-1)^2 - 4 * 1 * (-12)

∆ = 1 + 48

∆ = 49

∆ =√49

∆ = 7

X ' = 1 + 7/2

X ' = 8/2

X ' = 4

X " = 1 - 7/2

X " = - 6/2

X " = - 3

S = { - 3 , 4 }

Answer 2

usando delta

Δ = b²-4ac

Δ = 1²-4(-1)(12)

Δ = 1 + 48

Δ = 49

x₁ = -b+√Δ/2a

x₁ = -1+√49/2.(-1)

x₁ = -1+7/-2

x₁ = 6/-2

x₁= -3

x₂ = -b-√Δ/2a

x₂ = -b-√49/2.(-1)

x₂ = -1-7/-2

x₂ = -8/-2

x₂ = 4

S = { - 3 , 4 }