Question

(x+2).(x+4) qual essa bhaskara?

Answer 1

(x+2)(x+4)
x^2+4x+2x+8=
x^2+6x+8=0

A parti daí faça bhaskara: x':-2/ x":-4

Answer 2

(x+2)*(x+4)
x²+4x+2x+8
x²+6x+8=0

x = (-6 +- √36-32)/2
x' = (-6 + 2)/2
x' = -2

x" = (-6 - 2)/2
x" = -4