Question

Me ajudem a resolver estas expressões númericas.. obrigada
70-[5x(2^2/4)+3^2]
6^2/3^2+4x10-12
30+[6^2/(5-3)+1]
50+[3^2/(1+2)+4x3]
20-[6-4x(10-3^2)+1]
100-[6-4x(10-3^2)+1]
[4^2+(5-3)^3] / (9-7)^3

Answer 1

70-(5.4/4)+9=70-5+9=74
36/9+40-12=44-12=32
30+(36/2)+1 = 30+18+1 = 49
50+(9/3)+12 = 50+3+12 = 65
20-[6-4.(10-9)+1]= 20-(6-4+1) = 20-3 = 17
100-[6-4.(10-9)+1] = 100-(6-4+1) = 100-3 = 97
(16+2³)/2³ = (16+8)/8 = 24/8 = 3

Answer 2

Resposta:

70-(5.4/4)+9=70-5+9=74

36/9+40-12=44-12=32

30+(36/2)+1 = 30+18+1 = 49

50+(9/3)+12 = 50+3+12 = 65

20-[6-4.(10-9)+1]= 20-(6-4+1) = 20-3 = 17

100-[6-4.(10-9)+1] = 100-(6-4+1) = 100-3 = 97

(16+2³)/2³ = (16+8)/8 = 24/8 = 3

Explicação passo-a-passo:

hl4