Question

Mim ajudem por favor
{[(8×4+3)÷7+(3+15÷5)×3]×2-(19-7÷6}×6+12​

Answer 1

Explicação passo-a-passo:

{[(8×4+3)÷7+(3+15÷5)×3]×2-(19-7÷6)}×6+12

={[(32+3)÷7+(3+3)×3]×2-(19-7÷6)}×6+12

={[35÷7+6×3]×2-(19-7÷6)}×6+12

={[5+18]×2-(19-7÷6)}×6+12

={23×2-(12÷6)}×6+12

={23×2-2}×6+12

={46-2}×6+12

=44×6+12

=264+12

=276