Question

Determine o valor de sen x e sen y no triângulo a seguir.​

Answer 1

$\frac{12 \sqrt{2} }{ \sin(135) } = \frac{12}{ \sin(x) } \\ 12 \sqrt{2} \sin(x) = 12 \sin(135) \\ \sin(x) = \frac{ \sin(135) }{ \sqrt{2} }$

$\sin(x) = \frac{ \frac{ \sqrt{2} }{2} }{ \sqrt{2} } = \frac{ \sqrt{2} }{2} . \frac{1}{ \sqrt{2}} = \frac{1}{2}$

$\frac{12}{ \sin(x) } = \frac{8}{ \sin(y) } \\ 12 \sin(y) = 8 \sin(x) \\ 12 \sin(y) = 8. \frac{1}{2} \\ 12 \sin(y) = 4$

$\sin(y) = \frac{4}{12} \\ \sin(y) = \frac{1}{3}$