Question

resolva usando a equaçao do 2 grau x^2-x-6=0

Answer 1

Resposta:

Explicação passo-a-passo:

x²-x-6 = 0

Δ = b² - 4ac

Δ = -1² - 4.1.(-6)

Δ = 1 + 24

Δ = 25

x = -b +- √Δ / 2a

x' = (1 + 5) / 2

x' = 6 / 2

x' = 3

x'' = (1 - 5) / 2

x'' = -4 / 2

x'' = -2

S = (3; -2)

Answer 2

Resposta:

Explicação passo-a-passo:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}-x-6=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=-1~e~c=-6\\\\\Delta=(b)^{2}-4(a)(c)=(-1)^{2}-4(1)(-6)=1-(-24)=25\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-1)-\sqrt{25}}{2(1)}=\frac{1-5}{2}=\frac{-4}{2}=-2\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-1)+\sqrt{25}}{2(1)}=\frac{1+5}{2}=\frac{6}{2}=3\\\\S=\{-2,~3\}$