Question

Determine o valor de x em cada triângulo.
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Answer 1

a) 4²=x²+(√7)²

x²+7=16

x²=16-7

x²=9

x=√9

x=3

b)x²=3.12

x²=36

x=√36

x=6

c)7,5.x=4,5.6

7,5x=27

x=27/7,5

x=3,6

d)8²=16x

16x=64

x=64/16

x=4

e)4²=2.x

2x=16

x=16/2

x=8

f) x²=10.2,5

x²=25

x=√25

x=5