Respostas
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[1/(x+1) + 1/(1-x)].(x²-1) =
mmc (x+1) e (1-x) = (x+1).(1-x)
(x+1).(1-x):(x+1).1 = 1-x
(x+1).(1-x): (1-x) = x+1
[(x+1)+(1-x)]/(x+1).(1-x) . (x+1).(x-1) =
[(x+1)+(1-x)]/(1-x) . -(1-x) =
[(x+1)+(1-x)]/(-1) =
(x+1+1-x)/(-1) =
2/-1 = -2
mmc (x+1) e (1-x) = (x+1).(1-x)
(x+1).(1-x):(x+1).1 = 1-x
(x+1).(1-x): (1-x) = x+1
[(x+1)+(1-x)]/(x+1).(1-x) . (x+1).(x-1) =
[(x+1)+(1-x)]/(1-x) . -(1-x) =
[(x+1)+(1-x)]/(-1) =
(x+1+1-x)/(-1) =
2/-1 = -2
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