Question

Simplifique as frações algébricas

$\frac{8c}{4a}$

$\frac{ {4c}^{2} }{ {6c}^{3} }$

$\frac{abc}{cd}$

$\frac{ - 7 {a}^{3}c}{ - 21 {ac}^{5} }$

​

Answer 1

$\frac{8c}{4a} = \frac{2c}{a}$

$\frac{4 {c}^{2} }{6 {c}^{3} } = \frac{2}{3c}$

$\frac{ - 7 {a}^{3}c}{ - 21 {ac}^{5} } = \frac{ {a}^{2} }{3 {c}^{4} }$

$\frac{abc}{cd} = \frac{ab}{d}$