Question

deternine as raízes= 3x^2 - 5x+2=0​

Answer 1

Resposta:

S = {6; 1}

Explicação passo-a-passo:

3x² - 5x + 2 = 0

a = 3

b = - 5

c = 2

Calculando o Δ :

Δ = b² - 4.a.c  

Δ = - 63² - 4 . 9 . 54  

Δ = 3969 - 1944

Δ = 2025

Há 2 raízes reais.

Aplicando Bhaskara:

x = (- b ± √Δ)/2a

x' = - (- 63 ± √2025)/2.9

x' = 63 ± 45/18

x' = 63 + 45/18

x' = 108/18

x' = 6

x" = 63 - 45/18

x" = 18/18

x" = 1

S = {6; 1}

Bons estudos.

Answer 2

Resposta:

Explicação passo-a-passo:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~3x^{2}-5x+2=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=3{;}~b=-5~e~c=2\\\\\Delta=(b)^{2}-4(a)(c)=(-5)^{2}-4(3)(2)=25-(24)=1\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-5)-\sqrt{1}}{2(3)}=\frac{5-1}{6}=\frac{4\div2}{6\div2}=\frac{2}{3}\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-5)+\sqrt{1}}{2(3)}=\frac{5+1}{6}=\frac{6}{6}=1\\\\S=\{\frac{2}{3},~1\}$