Question

Dada a função y = 2 x 3 + 3 x 2 – 4 x + 1, o valor de y’(1) é:

Answer 1

$Sabemos\ que:\\ \\ f(x)=x^n\rightarrow\ f'(x) = n*x^{n-1}\\ \\ Logo:\\ \\ y=2x^3+3x^2-4x+1\\ \\ y'=2*3x^{3-1}+3*2x^{2-1}-4*x^{1-1}+0\\ \\ y' = 6x^2+6x-4\\ \\ y'(1) = 6*1^2+6*1-4\\ \\ y'(1) = 6+6-4\\ \\ \large\boxed{\therfore\ y'(1) = 8}$