Question

❌❌❌Ajuda urgente ❌❌❌
Fórmula de Bhaskara sem delta

4x^2+12x-27=0

Answer 1

Resposta:

A fórmula de Bhaskara utiliza o delta.

Explicação passo-a-passo:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~4x^{2}+12x-27=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=4{;}~b=12~e~c=-27\\\\\Delta=(b)^{2}-4(a)(c)=(12)^{2}-4(4)(-27)=144-(-432)=576\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(12)-\sqrt{576}}{2(4)}=\frac{-12-24}{8}=\frac{-36}{8}=-4,5\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(12)+\sqrt{576}}{2(4)}=\frac{-12+24}{8}=\frac{12}{8}=1,5\\\\S=\{-4,5,~1,5\}$