Question

resolva as equacoes fracionarias
3x/x-4=3+2/x(x=\,x=\4)

Answer 1

3x/(x-4) = 3 + 2/x
mmc de (x-4) e x = x.(x-4)
Resolvendo:
[x.(x-4):(x-4).3x]/x.(x-4) = [x.(x-4):x.3]/x.(x-4) + [x.(x-4):1.3]/x.(x-4)
Eliminando os denominadores:
x . 1 . 3x = (x-4).3 + 3.x.(x-4)
3x² = 3x-12 + 3x² - 12x
3x - 12x - 12 = 0
-9x - 12 = 0 .(-1)
9x + 12 = 0
9x = 12
x = 12/9
x = 4/3