Question

Escreva as equaçoes do 2 graus na
(2x-3)²=1+4x

Answer 1

Resposta:

$(2x - 3) {}^{2} = 1 + 4x$

$4x {}^{2} - 12x + 9 = 1 + 4x$

$4x {}^{2} - 12x + 9 - 1 - 4x = 0$

$4x {}^{2} - 16x + 8 = 0$

Coeficientes...

$a = 4 \\ b = - 16 \\ c = 8$

Delta...

$d = b {}^{2} - 4ac$

$d = ( - 16) {}^{2} - 4 \times 4 \times 8$

$d = 256 - 128$

$d = 128$

Bhaskara...

$x = \frac{ - b +/- \sqrt{d} }{2a}$

$x = \frac{ - ( - 4) +/- \sqrt{128} }{2.1}$

$x = \frac{4 +/- \sqrt{8} }{2}$

$x = \frac{4 +/- 2 \sqrt{2} }{2}$

$x1 = \frac{4 + 2 \sqrt{2} }{2} = \frac{2(2 + \sqrt{2}) }{2} = 2 + \sqrt{2} \\ x2 = \frac{4 - 2 \sqrt{2} }{2} = \frac{2(2 - \sqrt{2}) }{2} = 2 - \sqrt{2}$

Espero ter ajudado!!!