Question

resolver a expressao 7x[14+(4 ×5-3×6) elevado a 3]-18:9​

Answer 1

Resposta:

$7 \times [14+(4 ×5-3×6) {}^{3} ] \\ -18 \div 9$

$7 \times [14+(20-18) {}^{3} ]-18 \div 9$

$7 \times [14+(2) {}^{3} ]-18 \div 9$

$7 \times [14+8]-18 \div 9$

$7 \times 22 - 18 \div 9 \\ 154 - 2 = \\ 152$