Question

$\frac{1 + 3x}{2} \frac{ - 4x + 1}{3} = \frac{5 - x}{10} \frac{ + 2x + 6}{5}$
ajuda pfv​

Answer 1

Resposta:

$\frac{1+3x}{2}-\frac{4x+1}{3} =\frac{5-x}{10} +\frac{2x+6}{5} \\ \\ mmc=30\\ \\ \frac{15(1+3x)-10(4x+1)=3(5-x)+6(2x+6)}{30}\\ \\ despreze~o~denominador~30\\ \\ 15+45x-40x-10=15-3x+12x+36\\ \\ agrupe~os~termos~semelhantes\\ \\ 45x-40x+3x-12x=15+36-15+10\\ \\ -4x=46\\ \\ x=-\frac{46}{4} =-\frac{23}{2}~~ou~~-11,5$