Question

racionalizar o denominador de cada fração ​

Answer 1

Explicação passo-a-passo:

$a)\\ {6\sqrt{5} \over\sqrt{3} }={6\sqrt{5} .\sqrt{3} \over\sqrt{3} .\sqrt{3} }={6\sqrt{15} \over\sqrt{9} }={6\sqrt{15} \over3}=2\sqrt{15}$

$b)\\ {2\sqrt{6} \over3\sqrt{10} }={2\sqrt{6} .\sqrt{10} \over3.\sqrt{10} .\sqrt{10} }={2\sqrt{60} \over3\sqrt{100} }={2\sqrt{60} \over3.10}={2\sqrt{2^2.3.5} \over30}={4\sqrt{15} \over30}={2\sqrt{15} \over15}$